2y^2-5y+19=0

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Solution for 2y^2-5y+19=0 equation: 



2y^2-5y+19=0

a = 2; b = -5; c = +19;
Δ = b2-4ac
Δ = -52-4·2·19
Δ = -127
Delta is less than zero, so there is no solution for the equation

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